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(1/3)q^2-18q+120=0
Domain of the equation: 3)q^2!=0We add all the numbers together, and all the variables
q!=0/1
q!=0
q∈R
(+1/3)q^2-18q+120=0
We add all the numbers together, and all the variables
-18q+(+1/3)q^2+120=0
We multiply all the terms by the denominator
-18q*3)q^2+(+120*3)q^2+1=0
We add all the numbers together, and all the variables
-18q*3)q^2+360q^2+1=0
Wy multiply elements
-54q^2=0
a = -54; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-54)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$q=\frac{-b}{2a}=\frac{0}{-108}=0$
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